C++ in Action, w. CD-ROM: Industrial-strength Programming by Bartosz Milewski

By Bartosz Milewski

(Pearson schooling) sleek consultant to utilizing C++ langugage, together with tips on how to use it on home windows programming. exhibits the best way to write courses for programmers, no longer pcs. The CD-ROM beneficial properties all the resource code and initiatives from the textual content. additionally incorporates a significant other website. process necessities now not indexed. Softcover.

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And references. ) Can you imagine that there are people who claim to know C++, and even write programs in C++, without knowing all that? , and they will say: "What, constructors? I don't use them in C++. I declare all my variables at the top of the function (Member function? "). It's just a warning. When you rush to your office first thing tomorrow morning, panting, eager to share your new fascination with C++ with your fellow programmers, that's what you may encounter. Not to mention these programmers who will say: "C++ is too slow for me.

It's less error prone this way. Here’s the main procedure that passes an array to StrLen: int main () { char aString [] = "the long string"; int len = StrLen (aString); cout << "The length of " << aString << " is " << len; } We are scanning the string for a terminating null and returning the index of this null. Pretty obvious, isn’t it? Here’s a more traditional "optimized" version: int StrLen (char const * pStr) { char const * p = pStr; while (*p++); return p - pStr - 1; } We initialize p to point to the beginning of the string.

We do it using operator new. The memory returned by new is allocated from the so called heap—the area of memory managed by the C++ runtime. How do we access this new memory? Using a pointer to that particular type of variable or object. For instance, to get memory enough to store a single integer, we'd use the following syntax: int * pNumber = new int; Even better, we could (and presumably should) immediately initialize this memory with a particular value we want to store there: 60 int * pNumber = new int (2001); Figure 3.

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